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brENsKi user not visiting Queenzone.com
How shall we f**k off, Oh Lord
brENsKi
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Posted: 08 Feb 05, 17:27 Edit this post Reply to this post Reply with Quote


http://www.etienne.nu/imagepuz/trocoman.htm


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KillerQueen840 user not visiting Queenzone.com

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Posted: 08 Feb 05, 17:48 Edit this post Reply to this post Reply with Quote

Where do I put my answer? There were not any instructions on the page.


"The walls we build around us to keep sadness out also keep out the joy."

(Jim Rohn)
brENsKi user not visiting Queenzone.com
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Posted: 08 Feb 05, 17:53 Edit this post Reply to this post Reply with Quote

they are the last part of the web address inc htm


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wesi72 user not visiting Queenzone.com

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Posted: 08 Feb 05, 18:34 Edit this post Reply to this post Reply with Quote

Good site! Up to stage 7 now but need to go to bed! Plus it looks a bit tricky and I think I'll need to be awake to answer it!
Cheers,
Andrew


Cheers,

Andrew
Penetration_Guru user not visiting Queenzone.com
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Posted: 09 Feb 05, 15:55 Edit this post Reply to this post Reply with Quote

Error found

stage 2

777 + 1 * 2 * 3 * 4 * 5 * 6 * 7 * 8 * 9 * 0 = ZERO

The answer they want is 777 which you get from

777 + (1 * 2 * 3 * 4 * 5 * 6 * 7 * 8 * 9 * 0)


wesi72 user not visiting Queenzone.com

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Posted: 09 Feb 05, 18:12 Edit this post Reply to this post Reply with Quote

No, using BODMAS you do any multiplication first unless there are Brackets or Indices (Order), so their answer is correct.
To get zero you need to do something like:
(777+1)*2*3*4*5*6*7*8*9*0
or
(777+1*2*3*4*5*6*7*8*9)*0

HTH,
Andrew

PS still not done the rope in the lake problem - busy day at work!!!


Cheers,

Andrew
The Mir@cle user not visiting Queenzone.com
The Mir@cle
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Posted: 10 Feb 05, 05:23 Edit this post Reply to this post Reply with Quote

What's the answer of question 6???

Question:

A deck of cards contains 16 black cards and 4 red cards.
What is the probability of getting all 4 red cards if you randomly choose 4 cards from the deck?
1 in ?

I thought it was 100 / ( (4/20) * (3/19) * (2/18) * (1/17) ) and that's 1 in 484500... But that's not good.


I got to try al little more,

because I'm an asshole but I'm learning.



http://www.youtube.com/watch?v=NfTLkUcQ7QY
The Mir@cle user not visiting Queenzone.com
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Posted: 10 Feb 05, 06:01 Edit this post Reply to this post Reply with Quote

I have it... It's my answer above/100


I got to try al little more,

because I'm an asshole but I'm learning.



http://www.youtube.com/watch?v=NfTLkUcQ7QY
Tero user not visiting Queenzone.com

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Posted: 10 Feb 05, 12:07 Edit this post Reply to this post Reply with Quote

That was the only series I managed to go through without cheating... But I did have to take out my calculator for the trigonometric functions.

wesi72 user not visiting Queenzone.com

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Posted: 10 Feb 05, 12:29 Edit this post Reply to this post Reply with Quote

3) What is the probability of getting "heads" on every throw when flipping a coin seven times?
1 in ?

The probability of a head on the toss of a coin is 1/2.

If we throw it a second time the results are independent of each other so the probability is 1/2 again.

But, the probability of two heads in a row is 1/2 * 1/2 = 1/4 (another way to look at this is that you can get HH, HT, TH, TT and each is equally likely so that there is a 1 in 4 chance of two heads in a row)

Each time the coin is tossed, the number of possible outcomes doubles (ie, 3 tosses, 8 outcomes:- HHH, HHT, HTH, THH, HTT, TTH, THT, TTT), and there is always only 1 way you can get only heads.

So in 7 tosses, you need to work out how many possible outcomes there are if you keep doubling.

HTH,
Andrew




Cheers,

Andrew
brENsKi user not visiting Queenzone.com
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Posted: 10 Feb 05, 13:25 Edit this post Reply to this post Reply with Quote

the answers to ANY probability questions are not 1 in ????

they are just the "in" element - ie - if your answer is 1 in 25
then the answer to enter is 25


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